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2925141307 = 11318578127
BaseRepresentation
bin1010111001011010…
…0001110100111011
321112212011120111221
42232112201310323
521442314010212
61202131532511
7132326201524
oct25626416473
97485146457
102925141307
111271190a60
1269775a137
1337803435a
141da6bb84b
15121c08807
hexae5a1d3b

2925141307 has 8 divisors (see below), whose sum is σ = 3294001152. Its totient is φ = 2573437800.

The previous prime is 2925141299. The next prime is 2925141337. The reversal of 2925141307 is 7031415292.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2925141307 - 23 = 2925141299 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2925141337) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4288723 + ... + 4289404.

It is an arithmetic number, because the mean of its divisors is an integer number (411750144).

Almost surely, 22925141307 is an apocalyptic number.

2925141307 is a deficient number, since it is larger than the sum of its proper divisors (368859845).

2925141307 is a wasteful number, since it uses less digits than its factorization.

2925141307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8578169.

The product of its (nonzero) digits is 15120, while the sum is 34.

The square root of 2925141307 is about 54084.5754998595. The cubic root of 2925141307 is about 1430.1522825096.

Adding to 2925141307 its reverse (7031415292), we get a palindrome (9956556599).

The spelling of 2925141307 in words is "two billion, nine hundred twenty-five million, one hundred forty-one thousand, three hundred seven".

Divisors: 1 11 31 341 8578127 94359397 265921937 2925141307