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2949800158117 = 6988914220687
BaseRepresentation
bin101010111011001101110…
…010100110001110100101
3101102222221122102002022001
4222323031302212032211
5341312142320024432
610135041450405301
7423054540432661
oct52731562461645
911388848362261
102949800158117
11a3800431954a
123b7836130831
1318521b55cb57
14a2ab1c258a1
1551ae75769e7
hex2aecdca63a5

2949800158117 has 4 divisors (see below), whose sum is σ = 2949805077696. Its totient is φ = 2949795238540.

The previous prime is 2949800158093. The next prime is 2949800158159. The reversal of 2949800158117 is 7118510089492.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2949800158117 - 231 = 2947652674469 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2949800158187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1411453 + ... + 2809234.

It is an arithmetic number, because the mean of its divisors is an integer number (737451269424).

Almost surely, 22949800158117 is an apocalyptic number.

It is an amenable number.

2949800158117 is a deficient number, since it is larger than the sum of its proper divisors (4919579).

2949800158117 is an equidigital number, since it uses as much as digits as its factorization.

2949800158117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4919578.

The product of its (nonzero) digits is 1451520, while the sum is 55.

The spelling of 2949800158117 in words is "two trillion, nine hundred forty-nine billion, eight hundred million, one hundred fifty-eight thousand, one hundred seventeen".

Divisors: 1 698891 4220687 2949800158117