Base | Representation |
---|---|
bin | 101010111110010100001… |
… | …111011000000110100111 |
3 | 101110022112200022210212201 |
4 | 222332110033120012213 |
5 | 341341002133404312 |
6 | 10140352103555331 |
7 | 423233206232665 |
oct | 52762417300647 |
9 | 11408480283781 |
10 | 2953129591207 |
11 | a39462736944 |
12 | 3b840515bb47 |
13 | 18562c2790c3 |
14 | a2d0a0a3c35 |
15 | 51c3e9e0557 |
hex | 2af943d81a7 |
2953129591207 has 2 divisors, whose sum is σ = 2953129591208. Its totient is φ = 2953129591206.
The previous prime is 2953129591163. The next prime is 2953129591253. The reversal of 2953129591207 is 7021959213592.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2953129591207 - 211 = 2953129589159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2953129591267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1476564795603 + 1476564795604.
It is an arithmetic number, because the mean of its divisors is an integer number (1476564795604).
Almost surely, 22953129591207 is an apocalyptic number.
2953129591207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2953129591207 is an equidigital number, since it uses as much as digits as its factorization.
2953129591207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3061800, while the sum is 55.
The spelling of 2953129591207 in words is "two trillion, nine hundred fifty-three billion, one hundred twenty-nine million, five hundred ninety-one thousand, two hundred seven".
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