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299143000799 is a prime number
BaseRepresentation
bin1000101101001100100…
…11111111001011011111
31001121010210022221211222
410112212103333023133
514400121102011144
6345231400403555
730420020360366
oct4264623771337
91047123287758
10299143000799
111059584750a5
1249b864765bb
132229440c8a6
141069b3ba7dd
157bac3282ee
hex45a64ff2df

299143000799 has 2 divisors, whose sum is σ = 299143000800. Its totient is φ = 299143000798.

The previous prime is 299143000763. The next prime is 299143000801. The reversal of 299143000799 is 997000341992.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 299143000799 - 216 = 299142935263 is a prime.

Together with 299143000801, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 299143000799.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (299143000199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 149571500399 + 149571500400.

It is an arithmetic number, because the mean of its divisors is an integer number (149571500400).

Almost surely, 2299143000799 is an apocalyptic number.

299143000799 is a deficient number, since it is larger than the sum of its proper divisors (1).

299143000799 is an equidigital number, since it uses as much as digits as its factorization.

299143000799 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1102248, while the sum is 53.

The spelling of 299143000799 in words is "two hundred ninety-nine billion, one hundred forty-three million, seven hundred ninety-nine", and thus it is an aban number.