Base | Representation |
---|---|
bin | 101011101001111101111… |
… | …011110011000000110010 |
3 | 101121210112011021021111222 |
4 | 223221331323303000302 |
5 | 343123000000000200 |
6 | 10214103031305042 |
7 | 426512540154164 |
oct | 53517573630062 |
9 | 11553464237458 |
10 | 3000000000050 |
11 | a57324876819 |
12 | 405505b1b182 |
13 | 189b8b82cc31 |
14 | a52b4cd6934 |
15 | 53084743d85 |
hex | 2ba7def3032 |
3000000000050 has 48 divisors (see below), whose sum is σ = 5779659578112. Its totient is φ = 1157326699200.
The previous prime is 3000000000013. The next prime is 3000000000121. The reversal of 3000000000050 is 500000000003.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2999999999947 and 3000000000037.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2848724 + ... + 3757023.
It is an arithmetic number, because the mean of its divisors is an integer number (120409574544).
Almost surely, 23000000000050 is an apocalyptic number.
3000000000050 is a deficient number, since it is larger than the sum of its proper divisors (2779659578062).
3000000000050 is a wasteful number, since it uses less digits than its factorization.
3000000000050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6606083 (or 6606078 counting only the distinct ones).
The product of its (nonzero) digits is 15, while the sum is 8.
Adding to 3000000000050 its reverse (500000000003), we get a palindrome (3500000000053).
The spelling of 3000000000050 in words is "three trillion, fifty", and thus it is an aban number and an uban number.
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