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300000000035 = 566617900671
BaseRepresentation
bin1000101110110010110…
…01001011100000100011
31001200100111221000210102
410113121121023200203
514403400000000120
6345452413053015
730450164632421
oct4273131134043
91050314830712
10300000000035
111062581a732a
124a18548716b
132239cb2b928
141073d142111
157c0c6add75
hex45d964b823

300000000035 has 8 divisors (see below), whose sum is σ = 360005803776. Its totient is φ = 239996130880.

The previous prime is 299999999989. The next prime is 300000000077. The reversal of 300000000035 is 530000000003.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 300000000035 - 214 = 299999983651 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 299999999944 and 300000000025.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117251 + ... + 783420.

It is an arithmetic number, because the mean of its divisors is an integer number (45000725472).

Almost surely, 2300000000035 is an apocalyptic number.

300000000035 is a deficient number, since it is larger than the sum of its proper divisors (60005803741).

300000000035 is an equidigital number, since it uses as much as digits as its factorization.

300000000035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 967293.

The product of its (nonzero) digits is 45, while the sum is 11.

Adding to 300000000035 its reverse (530000000003), we get a palindrome (830000000038).

The spelling of 300000000035 in words is "three hundred billion, thirty-five", and thus it is an aban number.

Divisors: 1 5 66617 333085 900671 4503355 60000000007 300000000035