3000000401 has 2 divisors, whose sum is σ = 3000000402. Its totient is φ = 3000000400.

The previous prime is 3000000397. The next prime is 3000000403. The reversal of 3000000401 is 1040000003.

3000000401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2304096001 + 695904400 = 48001^2 + 26380^2 .

It is a cyclic number.

It is not a de Polignac number, because 3000000401 - 2² = 3000000397 is a prime.

Together with 3000000403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3000000403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1500000200 + 1500000201.

It is an arithmetic number, because the mean of its divisors is an integer number (1500000201).

Almost surely, 2^3000000401 is an apocalyptic number.

It is an amenable number.

3000000401 is a deficient number, since it is larger than the sum of its proper divisors (1).

3000000401 is an equidigital number, since it uses as much as digits as its factorization.

3000000401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 8.

The square root of 3000000401 is about 54772.2594111289. The cubic root of 3000000401 is about 1442.2496345676.

Adding to 3000000401 its reverse (1040000003), we get a palindrome (4040000404).

The spelling of 3000000401 in words is "three billion, four hundred one", and thus it is an aban number.