Base | Representation |
---|---|
bin | 100010000110110010110111… |
… | …0111001001000101110100111 |
3 | 1110100012211002200012102022222 |
4 | 1010031211232321020232213 |
5 | 303310204102432130043 |
6 | 2542014323204542555 |
7 | 120122234135104046 |
oct | 10415455671105647 |
9 | 1410184080172288 |
10 | 300001031130023 |
11 | 876537a50757a3 |
12 | 297922623b1a5b |
13 | cb51c8bc21422 |
14 | 54121ad76855d |
15 | 24a3aae13dd68 |
hex | 110d96ee48ba7 |
300001031130023 has 2 divisors, whose sum is σ = 300001031130024. Its totient is φ = 300001031130022.
The previous prime is 300001031129983. The next prime is 300001031130067. The reversal of 300001031130023 is 320031130100003.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 300001031130023 - 210 = 300001031128999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 300001031129983 and 300001031130010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (300001031160023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150000515565011 + 150000515565012.
It is an arithmetic number, because the mean of its divisors is an integer number (150000515565012).
Almost surely, 2300001031130023 is an apocalyptic number.
300001031130023 is a deficient number, since it is larger than the sum of its proper divisors (1).
300001031130023 is an equidigital number, since it uses as much as digits as its factorization.
300001031130023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 300001031130023 its reverse (320031130100003), we get a palindrome (620032161230026).
The spelling of 300001031130023 in words is "three hundred trillion, one billion, thirty-one million, one hundred thirty thousand, twenty-three".
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