Base | Representation |
---|---|
bin | 1101101001000111100101… |
… | …01100000100001101111011 |
3 | 10221012222120011120122120202 |
4 | 12310203302230010031323 |
5 | 12413010223021430042 |
6 | 143445511044312415 |
7 | 6214303010014424 |
oct | 664436254041573 |
9 | 127188504518522 |
10 | 30000123233147 |
11 | 9616a87510a31 |
12 | 34462846a270b |
13 | 1397ccbb28982 |
14 | 75a0298a864b |
15 | 37058aa1c632 |
hex | 1b48f2b0437b |
30000123233147 has 2 divisors, whose sum is σ = 30000123233148. Its totient is φ = 30000123233146.
The previous prime is 30000123233111. The next prime is 30000123233149. The reversal of 30000123233147 is 74133232100003.
It is a strong prime.
It is an emirp because it is prime and its reverse (74133232100003) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30000123233147 - 212 = 30000123229051 is a prime.
Together with 30000123233149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (30000123233149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15000061616573 + 15000061616574.
It is an arithmetic number, because the mean of its divisors is an integer number (15000061616574).
Almost surely, 230000123233147 is an apocalyptic number.
30000123233147 is a deficient number, since it is larger than the sum of its proper divisors (1).
30000123233147 is an equidigital number, since it uses as much as digits as its factorization.
30000123233147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 29.
The spelling of 30000123233147 in words is "thirty trillion, one hundred twenty-three million, two hundred thirty-three thousand, one hundred forty-seven".
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