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300014351453 is a prime number
BaseRepresentation
bin1000101110110100011…
…11111011010001011101
31001200101111221011020102
410113122033323101131
514403412133221303
6345454044430445
730450430624325
oct4273217732135
91050344834212
10300014351453
11106265309803
124a18a248425
13223a2ab4cab
1410740dda285
157c0da96288
hex45da3fb45d

300014351453 has 2 divisors, whose sum is σ = 300014351454. Its totient is φ = 300014351452.

The previous prime is 300014351407. The next prime is 300014351479. The reversal of 300014351453 is 354153410003.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 297796129849 + 2218221604 = 545707^2 + 47098^2 .

It is a cyclic number.

It is not a de Polignac number, because 300014351453 - 210 = 300014350429 is a prime.

It is a super-2 number, since 2×3000143514532 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (300014351753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150007175726 + 150007175727.

It is an arithmetic number, because the mean of its divisors is an integer number (150007175727).

Almost surely, 2300014351453 is an apocalyptic number.

It is an amenable number.

300014351453 is a deficient number, since it is larger than the sum of its proper divisors (1).

300014351453 is an equidigital number, since it uses as much as digits as its factorization.

300014351453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 300014351453 its reverse (354153410003), we get a palindrome (654167761456).

The spelling of 300014351453 in words is "three hundred billion, fourteen million, three hundred fifty-one thousand, four hundred fifty-three".