Base | Representation |
---|---|
bin | 1101101010010010001111… |
… | …01000001111100101100001 |
3 | 10221100211000101201202212002 |
4 | 12311021013220033211201 |
5 | 12414134313432001121 |
6 | 143520140113013345 |
7 | 6220222143301214 |
oct | 665110750174541 |
9 | 127324011652762 |
10 | 30040203000161 |
11 | 9631a844a1122 |
12 | 3451bab254255 |
13 | 139ba18589543 |
14 | 75bd4c8bb77b |
15 | 37163450de0b |
hex | 1b5247a0f961 |
30040203000161 has 2 divisors, whose sum is σ = 30040203000162. Its totient is φ = 30040203000160.
The previous prime is 30040203000131. The next prime is 30040203000163. The reversal of 30040203000161 is 16100030204003.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29749595753761 + 290607246400 = 5454319^2 + 539080^2 .
It is a cyclic number.
It is not a de Polignac number, because 30040203000161 - 210 = 30040202999137 is a prime.
Together with 30040203000163, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (30040203000163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15020101500080 + 15020101500081.
It is an arithmetic number, because the mean of its divisors is an integer number (15020101500081).
Almost surely, 230040203000161 is an apocalyptic number.
It is an amenable number.
30040203000161 is a deficient number, since it is larger than the sum of its proper divisors (1).
30040203000161 is an equidigital number, since it uses as much as digits as its factorization.
30040203000161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 30040203000161 its reverse (16100030204003), we get a palindrome (46140233204164).
The spelling of 30040203000161 in words is "thirty trillion, forty billion, two hundred three million, one hundred sixty-one", and thus it is an aban number.
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