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30040203000131 is a prime number
BaseRepresentation
bin1101101010010010001111…
…01000001111100101000011
310221100211000101201202210222
412311021013220033211003
512414134313432001011
6143520140113013255
76220222143301142
oct665110750174503
9127324011652728
1030040203000131
119631a844a10a5
123451bab25422b
13139ba1858951c
1475bd4c8bb759
1537163450dddb
hex1b5247a0f943

30040203000131 has 2 divisors, whose sum is σ = 30040203000132. Its totient is φ = 30040203000130.

The previous prime is 30040203000079. The next prime is 30040203000161. The reversal of 30040203000131 is 13100030204003.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (13100030204003) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-30040203000131 is a prime.

It is a super-2 number, since 2×300402030001312 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (30040203000161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15020101500065 + 15020101500066.

It is an arithmetic number, because the mean of its divisors is an integer number (15020101500066).

Almost surely, 230040203000131 is an apocalyptic number.

30040203000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

30040203000131 is an equidigital number, since it uses as much as digits as its factorization.

30040203000131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 30040203000131 its reverse (13100030204003), we get a palindrome (43140233204134).

The spelling of 30040203000131 in words is "thirty trillion, forty billion, two hundred three million, one hundred thirty-one", and thus it is an aban number.