Base | Representation |
---|---|
bin | 1101101100010110100010… |
… | …10110111101101111010111 |
3 | 10221121121100121120221120021 |
4 | 12312023101112331233113 |
5 | 12421320301200000114 |
6 | 144012524244450011 |
7 | 6225315300124153 |
oct | 666132126755727 |
9 | 127547317527507 |
10 | 30111233203159 |
11 | 965a114165a29 |
12 | 34639130a9907 |
13 | 13a5628287564 |
14 | 76156a264063 |
15 | 3733e02ba024 |
hex | 1b62d15bdbd7 |
30111233203159 has 2 divisors, whose sum is σ = 30111233203160. Its totient is φ = 30111233203158.
The previous prime is 30111233203157. The next prime is 30111233203211. The reversal of 30111233203159 is 95130233211103.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 30111233203159 - 21 = 30111233203157 is a prime.
It is a super-3 number, since 3×301112332031593 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 30111233203157, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30111233203151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15055616601579 + 15055616601580.
It is an arithmetic number, because the mean of its divisors is an integer number (15055616601580).
Almost surely, 230111233203159 is an apocalyptic number.
30111233203159 is a deficient number, since it is larger than the sum of its proper divisors (1).
30111233203159 is an equidigital number, since it uses as much as digits as its factorization.
30111233203159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 34.
The spelling of 30111233203159 in words is "thirty trillion, one hundred eleven billion, two hundred thirty-three million, two hundred three thousand, one hundred fifty-nine".
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