301113130013 has 2 divisors, whose sum is σ = 301113130014. Its totient is φ = 301113130012.

The previous prime is 301113129943. The next prime is 301113130067. The reversal of 301113130013 is 310031311103.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 295443341209 + 5669788804 = 543547^2 + 75298^2 .

It is an emirp because it is prime and its reverse (310031311103) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 301113130013 - 2¹⁰ = 301113128989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 301113129973 and 301113130000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (301113135013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150556565006 + 150556565007.

It is an arithmetic number, because the mean of its divisors is an integer number (150556565007).

Almost surely, 2^301113130013 is an apocalyptic number.

It is an amenable number.

301113130013 is a deficient number, since it is larger than the sum of its proper divisors (1).

301113130013 is an equidigital number, since it uses as much as digits as its factorization.

301113130013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 301113130013 its reverse (310031311103), we get a palindrome (611144441116).

The spelling of 301113130013 in words is "three hundred one billion, one hundred thirteen million, one hundred thirty thousand, thirteen".