Base | Representation |
---|---|
bin | 1000110000110111011… |
… | …11011100001111011001 |
3 | 1001210020002110222202222 |
4 | 10120123233130033121 |
5 | 14413134430210433 |
6 | 350155055233425 |
7 | 30516602251202 |
oct | 4303357341731 |
9 | 1053202428688 |
10 | 301113131993 |
11 | 1067795708a3 |
12 | 4a436218875 |
13 | 225196298ab |
14 | 10806cdc5a9 |
15 | 7c7528ab98 |
hex | 461bbdc3d9 |
301113131993 has 2 divisors, whose sum is σ = 301113131994. Its totient is φ = 301113131992.
The previous prime is 301113131951. The next prime is 301113132109. The reversal of 301113131993 is 399131311103.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 184799393689 + 116313738304 = 429883^2 + 341048^2 .
It is a cyclic number.
It is not a de Polignac number, because 301113131993 - 236 = 232393655257 is a prime.
It is not a weakly prime, because it can be changed into another prime (301113631993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150556565996 + 150556565997.
It is an arithmetic number, because the mean of its divisors is an integer number (150556565997).
Almost surely, 2301113131993 is an apocalyptic number.
It is an amenable number.
301113131993 is a deficient number, since it is larger than the sum of its proper divisors (1).
301113131993 is an equidigital number, since it uses as much as digits as its factorization.
301113131993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6561, while the sum is 35.
The spelling of 301113131993 in words is "three hundred one billion, one hundred thirteen million, one hundred thirty-one thousand, nine hundred ninety-three".
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