3011310013013 has 2 divisors, whose sum is σ = 3011310013014. Its totient is φ = 3011310013012.

The previous prime is 3011310012973. The next prime is 3011310013027. The reversal of 3011310013013 is 3103100131103.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2470310045284 + 540999967729 = 1571722^2 + 735527^2 .

It is a cyclic number.

It is not a de Polignac number, because 3011310013013 - 2²⁶ = 3011242904149 is a prime.

It is a super-3 number, since 3×3011310013013³ (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3011310012982 and 3011310013000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3011310013043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1505655006506 + 1505655006507.

It is an arithmetic number, because the mean of its divisors is an integer number (1505655006507).

Almost surely, 2^{3011310013013} is an apocalyptic number.

It is an amenable number.

3011310013013 is a deficient number, since it is larger than the sum of its proper divisors (1).

3011310013013 is an equidigital number, since it uses as much as digits as its factorization.

3011310013013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 3011310013013 its reverse (3103100131103), we get a palindrome (6114410144116).

The spelling of 3011310013013 in words is "three trillion, eleven billion, three hundred ten million, thirteen thousand, thirteen".