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30113120003 = 101298149703
BaseRepresentation
bin11100000010111000…
…011011111100000011
32212201122010222211212
4130002320123330003
5443132424320003
621500032400335
72114142203531
oct340270337403
985648128755
1030113120003
111185308683a
125a049a60ab
132abb950605
141659493151
15bb3a20dd8
hex702e1bf03

30113120003 has 4 divisors (see below), whose sum is σ = 30411269808. Its totient is φ = 29814970200.

The previous prime is 30113119999. The next prime is 30113120029. The reversal of 30113120003 is 30002131103.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 30113120003 - 22 = 30113119999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 30113120003.

It is not an unprimeable number, because it can be changed into a prime (30113120603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149074751 + ... + 149074952.

It is an arithmetic number, because the mean of its divisors is an integer number (7602817452).

Almost surely, 230113120003 is an apocalyptic number.

30113120003 is a deficient number, since it is larger than the sum of its proper divisors (298149805).

30113120003 is a wasteful number, since it uses less digits than its factorization.

30113120003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 298149804.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 30113120003 its reverse (30002131103), we get a palindrome (60115251106).

The spelling of 30113120003 in words is "thirty billion, one hundred thirteen million, one hundred twenty thousand, three".

Divisors: 1 101 298149703 30113120003