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3012113121301 is a prime number
BaseRepresentation
bin101011110101001111111…
…011101100000000010101
3101122221210100020121001101
4223311033323230000111
5343322301424340201
610223425021430101
7430421654042404
oct53651773540025
911587710217041
103012113121301
11a61480371029
1240792670b331
1318b06c2506bb
14a5b0395d63b
1553542dabd01
hex2bd4feec015

3012113121301 has 2 divisors, whose sum is σ = 3012113121302. Its totient is φ = 3012113121300.

The previous prime is 3012113121263. The next prime is 3012113121319. The reversal of 3012113121301 is 1031213112103.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2706110540676 + 306002580625 = 1645026^2 + 553175^2 .

It is an emirp because it is prime and its reverse (1031213112103) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3012113121301 - 233 = 3003523186709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3012113121361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506056560650 + 1506056560651.

It is an arithmetic number, because the mean of its divisors is an integer number (1506056560651).

Almost surely, 23012113121301 is an apocalyptic number.

It is an amenable number.

3012113121301 is a deficient number, since it is larger than the sum of its proper divisors (1).

3012113121301 is an equidigital number, since it uses as much as digits as its factorization.

3012113121301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 3012113121301 its reverse (1031213112103), we get a palindrome (4043326233404).

The spelling of 3012113121301 in words is "three trillion, twelve billion, one hundred thirteen million, one hundred twenty-one thousand, three hundred one".