Base | Representation |
---|---|
bin | 101011110110001100000… |
… | …100101000101110000111 |
3 | 101200001101122211000202122 |
4 | 223312030010220232013 |
5 | 343331333224200403 |
6 | 10224113103400155 |
7 | 430455655160513 |
oct | 53661404505607 |
9 | 11601348730678 |
10 | 3013122100103 |
11 | a61948967805 |
12 | 407b685b305b |
13 | 18b1a02b268b |
14 | a5b9b967143 |
15 | 535a1763838 |
hex | 2bd8c128b87 |
3013122100103 has 2 divisors, whose sum is σ = 3013122100104. Its totient is φ = 3013122100102.
The previous prime is 3013122100099. The next prime is 3013122100139. The reversal of 3013122100103 is 3010012213103.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3013122100103 - 22 = 3013122100099 is a prime.
It is a super-3 number, since 3×30131221001033 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3013122100003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506561050051 + 1506561050052.
It is an arithmetic number, because the mean of its divisors is an integer number (1506561050052).
Almost surely, 23013122100103 is an apocalyptic number.
3013122100103 is a deficient number, since it is larger than the sum of its proper divisors (1).
3013122100103 is an equidigital number, since it uses as much as digits as its factorization.
3013122100103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 3013122100103 its reverse (3010012213103), we get a palindrome (6023134313206).
The spelling of 3013122100103 in words is "three trillion, thirteen billion, one hundred twenty-two million, one hundred thousand, one hundred three".
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