Base | Representation |
---|---|
bin | 1101101100111101110010… |
… | …00011101001100100011111 |
3 | 10221200121201211002112011220 |
4 | 12312132321003221210133 |
5 | 12422141422340314403 |
6 | 144030330534144423 |
7 | 6226662330522006 |
oct | 666367103514437 |
9 | 127617654075156 |
10 | 30132300323103 |
11 | 9668044a91a60 |
12 | 3467a124b2113 |
13 | 13a7604a6ccc4 |
14 | 7625a8169c3d |
15 | 373c24a74953 |
hex | 1b67b90e991f |
30132300323103 has 64 divisors (see below), whose sum is σ = 45178302873600. Its totient is φ = 17703437880960.
The previous prime is 30132300323101. The next prime is 30132300323113.
30132300323103 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 30132300323103 - 21 = 30132300323101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30132300323101) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 388870518 + ... + 388947996.
It is an arithmetic number, because the mean of its divisors is an integer number (705910982400).
Almost surely, 230132300323103 is an apocalyptic number.
30132300323103 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
30132300323103 is a deficient number, since it is larger than the sum of its proper divisors (15046002550497).
30132300323103 is a wasteful number, since it uses less digits than its factorization.
30132300323103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78692.
The product of its (nonzero) digits is 2916, while the sum is 24.
It can be divided in two parts, 30132300 and 323103, that added together give a palindrome (30455403).
The spelling of 30132300323103 in words is "thirty trillion, one hundred thirty-two billion, three hundred million, three hundred twenty-three thousand, one hundred three".
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