Base | Representation |
---|---|
bin | 101011110110010010100… |
… | …100011110111110110001 |
3 | 101200001200020221102010111 |
4 | 223312102210132332301 |
5 | 343332044131041423 |
6 | 10224132000101321 |
7 | 430461450566005 |
oct | 53662244367661 |
9 | 11601606842114 |
10 | 3013231112113 |
11 | a619a4454082 |
12 | 407b99004841 |
13 | 18b1b9a60121 |
14 | a5bac222705 |
15 | 535ab0e860d |
hex | 2bd9291efb1 |
3013231112113 has 2 divisors, whose sum is σ = 3013231112114. Its totient is φ = 3013231112112.
The previous prime is 3013231112071. The next prime is 3013231112137. The reversal of 3013231112113 is 3112111323103.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2840650688929 + 172580423184 = 1685423^2 + 415428^2 .
It is a cyclic number.
It is not a de Polignac number, because 3013231112113 - 213 = 3013231103921 is a prime.
It is not a weakly prime, because it can be changed into another prime (3013231112153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506615556056 + 1506615556057.
It is an arithmetic number, because the mean of its divisors is an integer number (1506615556057).
Almost surely, 23013231112113 is an apocalyptic number.
It is an amenable number.
3013231112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3013231112113 is an equidigital number, since it uses as much as digits as its factorization.
3013231112113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 3013231112113 its reverse (3112111323103), we get a palindrome (6125342435216).
The spelling of 3013231112113 in words is "three trillion, thirteen billion, two hundred thirty-one million, one hundred twelve thousand, one hundred thirteen".
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