Base | Representation |
---|---|
bin | 101101010010011000010… |
… | …010100011011111011111 |
3 | 102000111220101111120122011 |
4 | 231102120102203133133 |
5 | 401442100444314403 |
6 | 10341403442132051 |
7 | 440562006531346 |
oct | 55223022433737 |
9 | 12014811446564 |
10 | 3112111323103 |
11 | a9a925789112 |
12 | 423193951027 |
13 | 197617580803 |
14 | aa8ac672b5d |
15 | 55e46d8da6d |
hex | 2d4984a37df |
3112111323103 has 4 divisors (see below), whose sum is σ = 3247420511088. Its totient is φ = 2976802135120.
The previous prime is 3112111323091. The next prime is 3112111323107. The reversal of 3112111323103 is 3013231112113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3112111323103 - 217 = 3112111192031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3112111323107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67654593958 + ... + 67654594003.
It is an arithmetic number, because the mean of its divisors is an integer number (811855127772).
Almost surely, 23112111323103 is an apocalyptic number.
3112111323103 is a deficient number, since it is larger than the sum of its proper divisors (135309187985).
3112111323103 is a wasteful number, since it uses less digits than its factorization.
3112111323103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 135309187984.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 3112111323103 its reverse (3013231112113), we get a palindrome (6125342435216).
The spelling of 3112111323103 in words is "three trillion, one hundred twelve billion, one hundred eleven million, three hundred twenty-three thousand, one hundred three".
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