301421011413 has 4 divisors (see below), whose sum is σ = 401894681888. Its totient is φ = 200947340940.

The previous prime is 301421011399. The next prime is 301421011447. The reversal of 301421011413 is 314110124103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 314110124103 = 3 ⋅104703374701.

It is not a de Polignac number, because 301421011413 - 2²¹ = 301418914261 is a prime.

It is a super-4 number, since 4×301421011413⁴ (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 301421011413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (301421011453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50236835233 + ... + 50236835238.

It is an arithmetic number, because the mean of its divisors is an integer number (100473670472).

Almost surely, 2^301421011413 is an apocalyptic number.

It is an amenable number.

301421011413 is a deficient number, since it is larger than the sum of its proper divisors (100473670475).

301421011413 is a wasteful number, since it uses less digits than its factorization.

301421011413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100473670474.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 301421011413 its reverse (314110124103), we get a palindrome (615531135516).

The spelling of 301421011413 in words is "three hundred one billion, four hundred twenty-one million, eleven thousand, four hundred thirteen".