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30142433121 = 369061145487
BaseRepresentation
bin11100000100101000…
…010000011101100001
32212210200022020212220
4130010220100131201
5443212430324441
621503000541253
72114646311523
oct340450203541
985720266786
1030142433121
1111868688159
125a12781829
132ac4a44a58
14165d323a13
15bb63b1466
hex704a10761

30142433121 has 8 divisors (see below), whose sum is σ = 40190769024. Its totient is φ = 20094526320.

The previous prime is 30142433077. The next prime is 30142433129. The reversal of 30142433121 is 12133424103.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 30142433121 - 211 = 30142431073 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 30142433091 and 30142433100.

It is not an unprimeable number, because it can be changed into a prime (30142433129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 134440 + ... + 279926.

It is an arithmetic number, because the mean of its divisors is an integer number (5023846128).

Almost surely, 230142433121 is an apocalyptic number.

It is an amenable number.

30142433121 is a deficient number, since it is larger than the sum of its proper divisors (10048335903).

30142433121 is a wasteful number, since it uses less digits than its factorization.

30142433121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 214551.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 30142433121 its reverse (12133424103), we get a palindrome (42275857224).

The spelling of 30142433121 in words is "thirty billion, one hundred forty-two million, four hundred thirty-three thousand, one hundred twenty-one".

Divisors: 1 3 69061 145487 207183 436461 10047477707 30142433121