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30204341335 = 57862981181
BaseRepresentation
bin11100001000010100…
…011010110001010111
32212221222210111222201
4130020110122301113
5443324302410320
621513051505331
72116330444120
oct341024326127
985858714881
1030204341335
111189a621773
125a2b458247
132b0480c42c
14166763b047
15bbba3e70a
hex70851ac57

30204341335 has 8 divisors (see below), whose sum is σ = 41423096736. Its totient is φ = 20711548320.

The previous prime is 30204341333. The next prime is 30204341353. The reversal of 30204341335 is 53314340203.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 30204341335 - 21 = 30204341333 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30204341333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 431490556 + ... + 431490625.

It is an arithmetic number, because the mean of its divisors is an integer number (5177887092).

Almost surely, 230204341335 is an apocalyptic number.

30204341335 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

30204341335 is a deficient number, since it is larger than the sum of its proper divisors (11218755401).

30204341335 is an equidigital number, since it uses as much as digits as its factorization.

30204341335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 862981193.

The product of its (nonzero) digits is 12960, while the sum is 28.

Adding to 30204341335 its reverse (53314340203), we get a palindrome (83518681538).

The spelling of 30204341335 in words is "thirty billion, two hundred four million, three hundred forty-one thousand, three hundred thirty-five".

Divisors: 1 5 7 35 862981181 4314905905 6040868267 30204341335