Base | Representation |
---|---|
bin | 1101101111010100001001… |
… | …01001011000100110100111 |
3 | 10221222100002200120101102020 |
4 | 12313222010221120212213 |
5 | 12430002234000320010 |
6 | 144131401112514223 |
7 | 6235550635414044 |
oct | 667520451304647 |
9 | 127870080511366 |
10 | 30213025401255 |
11 | 96992aa206a84 |
12 | 347b5a10ab973 |
13 | 13b20cb184b38 |
14 | 76646532a1cb |
15 | 375d9ba1b470 |
hex | 1b7a84a589a7 |
30213025401255 has 16 divisors (see below), whose sum is σ = 50885095413120. Its totient is φ = 15265528623648.
The previous prime is 30213025401149. The next prime is 30213025401263. The reversal of 30213025401255 is 55210452031203.
It is not a de Polignac number, because 30213025401255 - 216 = 30213025335719 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53005307437 + ... + 53005308006.
It is an arithmetic number, because the mean of its divisors is an integer number (3180318463320).
Almost surely, 230213025401255 is an apocalyptic number.
30213025401255 is a deficient number, since it is larger than the sum of its proper divisors (20672070011865).
30213025401255 is a wasteful number, since it uses less digits than its factorization.
30213025401255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106010615470.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 30213025401255 its reverse (55210452031203), we get a palindrome (85423477432458).
The spelling of 30213025401255 in words is "thirty trillion, two hundred thirteen billion, twenty-five million, four hundred one thousand, two hundred fifty-five".
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