Base | Representation |
---|---|
bin | 101100000110000001011… |
… | …010101100010000010011 |
3 | 101201200021111101110120210 |
4 | 230012001122230100103 |
5 | 344121143014422210 |
6 | 10240004104135203 |
7 | 431630164150122 |
oct | 54060132542023 |
9 | 11650244343523 |
10 | 3030123201555 |
11 | a6908260897a |
12 | 40b312167503 |
13 | 18c97c5a0218 |
14 | a6931851ab9 |
15 | 53c490a6e20 |
hex | 2c1816ac413 |
3030123201555 has 8 divisors (see below), whose sum is σ = 4848197122512. Its totient is φ = 1616065707488.
The previous prime is 3030123201473. The next prime is 3030123201577. The reversal of 3030123201555 is 5551023210303.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3030123201555 - 29 = 3030123201043 is a prime.
It is a super-3 number, since 3×30301232015553 (a number of 38 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101004106704 + ... + 101004106733.
It is an arithmetic number, because the mean of its divisors is an integer number (606024640314).
Almost surely, 23030123201555 is an apocalyptic number.
3030123201555 is a deficient number, since it is larger than the sum of its proper divisors (1818073920957).
3030123201555 is a wasteful number, since it uses less digits than its factorization.
3030123201555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 202008213445.
The product of its (nonzero) digits is 13500, while the sum is 30.
Adding to 3030123201555 its reverse (5551023210303), we get a palindrome (8581146411858).
The spelling of 3030123201555 in words is "three trillion, thirty billion, one hundred twenty-three million, two hundred one thousand, five hundred fifty-five".
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