Base | Representation |
---|---|
bin | 1101110010011100011010… |
… | …10001001101011010110111 |
3 | 10222100121121212020101020110 |
4 | 12321032031101031122313 |
5 | 12433232433311210320 |
6 | 144253022110434103 |
7 | 6246405231444105 |
oct | 671161521153267 |
9 | 128317555211213 |
10 | 30320544241335 |
11 | 972a9638509a7 |
12 | 34983a8b02933 |
13 | 13bc2a461aa7a |
14 | 76b744ba4c75 |
15 | 378a90daa5e0 |
hex | 1b938d44d6b7 |
30320544241335 has 64 divisors (see below), whose sum is σ = 52311143301120. Its totient is φ = 14947147313280.
The previous prime is 30320544241327. The next prime is 30320544241349. The reversal of 30320544241335 is 53314244502303.
It is not a de Polignac number, because 30320544241335 - 23 = 30320544241327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30320544241293 and 30320544241302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9806382 + ... + 12522228.
It is an arithmetic number, because the mean of its divisors is an integer number (817361614080).
Almost surely, 230320544241335 is an apocalyptic number.
30320544241335 is a deficient number, since it is larger than the sum of its proper divisors (21990599059785).
30320544241335 is a wasteful number, since it uses less digits than its factorization.
30320544241335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2716828.
The product of its (nonzero) digits is 518400, while the sum is 39.
Adding to 30320544241335 its reverse (53314244502303), we get a palindrome (83634788743638).
The spelling of 30320544241335 in words is "thirty trillion, three hundred twenty billion, five hundred forty-four million, two hundred forty-one thousand, three hundred thirty-five".
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