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3040213122014 = 22366091589609
BaseRepresentation
bin101100001111011010110…
…100101011101111011110
3101202122022200100112101112
4230033122310223233132
5344302324024401024
610244353222142022
7432435213103625
oct54173264535736
911678280315345
103040213122014
11a7239005a512
12411269281912
131908c9ab2363
14a720b9006bc
1554139cc800e
hex2c3dad2bbde

3040213122014 has 8 divisors (see below), whose sum is σ = 4758594451920. Its totient is φ = 1454014971376.

The previous prime is 3040213122007. The next prime is 3040213122019. The reversal of 3040213122014 is 4102213120403.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-4 number, since 4×30402131220144 (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3040213122019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33045794759 + ... + 33045794850.

It is an arithmetic number, because the mean of its divisors is an integer number (594824306490).

Almost surely, 23040213122014 is an apocalyptic number.

3040213122014 is a deficient number, since it is larger than the sum of its proper divisors (1718381329906).

3040213122014 is a wasteful number, since it uses less digits than its factorization.

3040213122014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66091589634.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 3040213122014 its reverse (4102213120403), we get a palindrome (7142426242417).

The spelling of 3040213122014 in words is "three trillion, forty billion, two hundred thirteen million, one hundred twenty-two thousand, fourteen".

Divisors: 1 2 23 46 66091589609 132183179218 1520106561007 3040213122014