Base | Representation |
---|---|
bin | 1101110101000011101001… |
… | …01001010010001110101111 |
3 | 10222200012100212101120220222 |
4 | 12322201310221102032233 |
5 | 12441220321302412221 |
6 | 144402151033201555 |
7 | 6256034133136163 |
oct | 672416451221657 |
9 | 128605325346828 |
10 | 30410325435311 |
11 | 9764a45a04868 |
12 | 34b18845602bb |
13 | 13c78b1cccc13 |
14 | 771c209c6ca3 |
15 | 37b097e159ab |
hex | 1ba874a523af |
30410325435311 has 2 divisors, whose sum is σ = 30410325435312. Its totient is φ = 30410325435310.
The previous prime is 30410325435299. The next prime is 30410325435313. The reversal of 30410325435311 is 11353452301403.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30410325435311 - 26 = 30410325435247 is a prime.
Together with 30410325435313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30410325435313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15205162717655 + 15205162717656.
It is an arithmetic number, because the mean of its divisors is an integer number (15205162717656).
Almost surely, 230410325435311 is an apocalyptic number.
30410325435311 is a deficient number, since it is larger than the sum of its proper divisors (1).
30410325435311 is an equidigital number, since it uses as much as digits as its factorization.
30410325435311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 30410325435311 its reverse (11353452301403), we get a palindrome (41763777736714).
The spelling of 30410325435311 in words is "thirty trillion, four hundred ten billion, three hundred twenty-five million, four hundred thirty-five thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •