Base | Representation |
---|---|
bin | 101100010000011100111… |
… | …111011100101100110011 |
3 | 101202202012001020101022111 |
4 | 230100130333130230303 |
5 | 344312112222141433 |
6 | 10245055315550151 |
7 | 432504553001131 |
oct | 54203477345463 |
9 | 11682161211274 |
10 | 3041323240243 |
11 | a728aa7557a2 |
12 | 411518bbb357 |
13 | 190a45a96652 |
14 | a72b5114751 |
15 | 541a24abdcd |
hex | 2c41cfdcb33 |
3041323240243 has 2 divisors, whose sum is σ = 3041323240244. Its totient is φ = 3041323240242.
The previous prime is 3041323240171. The next prime is 3041323240253. The reversal of 3041323240243 is 3420423231403.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3041323240243 is a prime.
It is not a weakly prime, because it can be changed into another prime (3041323240253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520661620121 + 1520661620122.
It is an arithmetic number, because the mean of its divisors is an integer number (1520661620122).
Almost surely, 23041323240243 is an apocalyptic number.
3041323240243 is a deficient number, since it is larger than the sum of its proper divisors (1).
3041323240243 is an equidigital number, since it uses as much as digits as its factorization.
3041323240243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 3041323240243 its reverse (3420423231403), we get a palindrome (6461746471646).
The spelling of 3041323240243 in words is "three trillion, forty-one billion, three hundred twenty-three million, two hundred forty thousand, two hundred forty-three".
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