Base | Representation |
---|---|
bin | 101100011011010111100… |
… | …011011001100100111101 |
3 | 101210212102211100001201122 |
4 | 230123113203121210331 |
5 | 400010113022131110 |
6 | 10254314302320325 |
7 | 433401153455366 |
oct | 54332743314475 |
9 | 11725384301648 |
10 | 3053043161405 |
11 | a778742a9a56 |
12 | 413849b890a5 |
13 | 191b92bb6943 |
14 | a7aa7866b6d |
15 | 5463b356255 |
hex | 2c6d78d993d |
3053043161405 has 4 divisors (see below), whose sum is σ = 3663651793692. Its totient is φ = 2442434529120.
The previous prime is 3053043161387. The next prime is 3053043161411. The reversal of 3053043161405 is 5041613403503.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 354047610361 + 2698995551044 = 595019^2 + 1642862^2 .
It is not a de Polignac number, because 3053043161405 - 210 = 3053043160381 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305304316136 + ... + 305304316145.
It is an arithmetic number, because the mean of its divisors is an integer number (915912948423).
Almost surely, 23053043161405 is an apocalyptic number.
It is an amenable number.
3053043161405 is a deficient number, since it is larger than the sum of its proper divisors (610608632287).
3053043161405 is an equidigital number, since it uses as much as digits as its factorization.
3053043161405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 610608632286.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 3053043161405 its reverse (5041613403503), we get a palindrome (8094656564908).
The spelling of 3053043161405 in words is "three trillion, fifty-three billion, forty-three million, one hundred sixty-one thousand, four hundred five".
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