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3054051131 is a prime number
BaseRepresentation
bin1011011000001001…
…0001111100111011
321212211201212112212
42312002101330323
522223314114011
61223014525335
7135453002105
oct26602217473
97784655485
103054051131
111327a288aa
1271296684b
1339895a861
1420d876575
1512d1be08b
hexb6091f3b

3054051131 has 2 divisors, whose sum is σ = 3054051132. Its totient is φ = 3054051130.

The previous prime is 3054051101. The next prime is 3054051137. The reversal of 3054051131 is 1311504503.

It is a strong prime.

It is an emirp because it is prime and its reverse (1311504503) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3054051131 - 218 = 3053788987 is a prime.

It is a super-2 number, since 2×30540511312 = 18654456621524758322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3054051097 and 3054051106.

It is not a weakly prime, because it can be changed into another prime (3054051137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527025565 + 1527025566.

It is an arithmetic number, because the mean of its divisors is an integer number (1527025566).

Almost surely, 23054051131 is an apocalyptic number.

3054051131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3054051131 is an equidigital number, since it uses as much as digits as its factorization.

3054051131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 3054051131 is about 55263.4701317244. The cubic root of 3054051131 is about 1450.8597566271.

Adding to 3054051131 its reverse (1311504503), we get a palindrome (4365555634).

The spelling of 3054051131 in words is "three billion, fifty-four million, fifty-one thousand, one hundred thirty-one".