Base | Representation |
---|---|
bin | 101100011101101101000… |
… | …000001010000001011111 |
3 | 101211002220120100022121021 |
4 | 230131231000022001133 |
5 | 400030231412130210 |
6 | 10255411151345011 |
7 | 433520250521236 |
oct | 54355500120137 |
9 | 11732816308537 |
10 | 3055550505055 |
11 | a78940669394 |
12 | 414229822167 |
13 | 1921a24b7839 |
14 | a7c64869b1d |
15 | 54736532bda |
hex | 2c76d00a05f |
3055550505055 has 4 divisors (see below), whose sum is σ = 3666660606072. Its totient is φ = 2444440404040.
The previous prime is 3055550505047. The next prime is 3055550505101. The reversal of 3055550505055 is 5505050555503.
3055550505055 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 3055550505055 - 23 = 3055550505047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305555050501 + ... + 305555050510.
It is an arithmetic number, because the mean of its divisors is an integer number (916665151518).
Almost surely, 23055550505055 is an apocalyptic number.
3055550505055 is a deficient number, since it is larger than the sum of its proper divisors (611110101017).
3055550505055 is an equidigital number, since it uses as much as digits as its factorization.
3055550505055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 611110101016.
The product of its (nonzero) digits is 1171875, while the sum is 43.
The spelling of 3055550505055 in words is "three trillion, fifty-five billion, five hundred fifty million, five hundred five thousand, fifty-five".
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