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30555549041 is a prime number
BaseRepresentation
bin11100011101010000…
…001010110101110001
32220212110122201101112
4130131100022311301
51000034210032131
622011555243105
72131123611233
oct343520126561
986773581345
1030555549041
1111a5a8a1276
125b08ba9495
132b5c4c9244
14169c140253
15bdc7b602b
hex71d40ad71

30555549041 has 2 divisors, whose sum is σ = 30555549042. Its totient is φ = 30555549040.

The previous prime is 30555548987. The next prime is 30555549043. The reversal of 30555549041 is 14094555503.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25638734641 + 4916814400 = 160121^2 + 70120^2 .

It is a cyclic number.

It is not a de Polignac number, because 30555549041 - 222 = 30551354737 is a prime.

Together with 30555549043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 30555549041.

It is not a weakly prime, because it can be changed into another prime (30555549043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15277774520 + 15277774521.

It is an arithmetic number, because the mean of its divisors is an integer number (15277774521).

Almost surely, 230555549041 is an apocalyptic number.

It is an amenable number.

30555549041 is a deficient number, since it is larger than the sum of its proper divisors (1).

30555549041 is an equidigital number, since it uses as much as digits as its factorization.

30555549041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270000, while the sum is 41.

The spelling of 30555549041 in words is "thirty billion, five hundred fifty-five million, five hundred forty-nine thousand, forty-one".