Base | Representation |
---|---|
bin | 11100110111101111… |
… | …100111011110111001 |
3 | 2222000102222012002111 |
4 | 130313233213132321 |
5 | 1001442000003231 |
6 | 22124033332321 |
7 | 2145131441014 |
oct | 346757473671 |
9 | 88012865074 |
10 | 31000000441 |
11 | 12168768183 |
12 | 6011a070a1 |
13 | 2c00602537 |
14 | 170119637b |
15 | c1680a4b1 |
hex | 737be77b9 |
31000000441 has 2 divisors, whose sum is σ = 31000000442. Its totient is φ = 31000000440.
The previous prime is 31000000439. The next prime is 31000000459. The reversal of 31000000441 is 14400000013.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30903882025 + 96118416 = 175795^2 + 9804^2 .
It is a cyclic number.
It is not a de Polignac number, because 31000000441 - 21 = 31000000439 is a prime.
It is a super-2 number, since 2×310000004412 (a number of 22 digits) contains 22 as substring.
Together with 31000000439, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (31000000541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15500000220 + 15500000221.
It is an arithmetic number, because the mean of its divisors is an integer number (15500000221).
Almost surely, 231000000441 is an apocalyptic number.
It is an amenable number.
31000000441 is a deficient number, since it is larger than the sum of its proper divisors (1).
31000000441 is an equidigital number, since it uses as much as digits as its factorization.
31000000441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 31000000441 its reverse (14400000013), we get a palindrome (45400000454).
The spelling of 31000000441 in words is "thirty-one billion, four hundred forty-one", and thus it is an aban number.
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