310012111212017 has 2 divisors, whose sum is σ = 310012111212018. Its totient is φ = 310012111212016.

The previous prime is 310012111211989. The next prime is 310012111212019. The reversal of 310012111212017 is 710212111210013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 182449746700816 + 127562364511201 = 13507396^2 + 11294351^2 .

It is a cyclic number.

It is not a de Polignac number, because 310012111212017 - 2¹⁶ = 310012111146481 is a prime.

It is a super-2 number, since 2×310012111212017² (a number of 30 digits) contains 22 as substring.

Together with 310012111212019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 310012111211983 and 310012111212001.

It is not a weakly prime, because it can be changed into another prime (310012111212019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155006055606008 + 155006055606009.

It is an arithmetic number, because the mean of its divisors is an integer number (155006055606009).

Almost surely, 2^{310012111212017} is an apocalyptic number.

It is an amenable number.

310012111212017 is a deficient number, since it is larger than the sum of its proper divisors (1).

310012111212017 is an equidigital number, since it uses as much as digits as its factorization.

310012111212017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 23.

The spelling of 310012111212017 in words is "three hundred ten trillion, twelve billion, one hundred eleven million, two hundred twelve thousand, seventeen".