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310213020041 is a prime number
BaseRepresentation
bin1001000001110100010…
…00110000100110001001
31002122201021112012102122
410200322020300212021
520040304013120131
6354302045341025
731261240110101
oct4407210604611
91078637465378
10310213020041
1110a619187431
1250155867775
13233399b1732
141102b6b6201
1581090e8d7b
hex483a230989

310213020041 has 2 divisors, whose sum is σ = 310213020042. Its totient is φ = 310213020040.

The previous prime is 310213020017. The next prime is 310213020043. The reversal of 310213020041 is 140020312013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 284111386441 + 26101633600 = 533021^2 + 161560^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-310213020041 is a prime.

Together with 310213020043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (310213020043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155106510020 + 155106510021.

It is an arithmetic number, because the mean of its divisors is an integer number (155106510021).

Almost surely, 2310213020041 is an apocalyptic number.

It is an amenable number.

310213020041 is a deficient number, since it is larger than the sum of its proper divisors (1).

310213020041 is an equidigital number, since it uses as much as digits as its factorization.

310213020041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 310213020041 its reverse (140020312013), we get a palindrome (450233332054).

The spelling of 310213020041 in words is "three hundred ten billion, two hundred thirteen million, twenty thousand, forty-one".