Base | Representation |
---|---|
bin | 1001000001110111111… |
… | …00010100000110011111 |
3 | 1002122210101112012020012 |
4 | 10200323330110012133 |
5 | 20040334241441111 |
6 | 354305050513435 |
7 | 31262055432662 |
oct | 4407374240637 |
9 | 1078711465205 |
10 | 310243312031 |
11 | 10a634297234 |
12 | 50163a3587b |
13 | 233430595a3 |
14 | 1103171d6d9 |
15 | 810bace48b |
hex | 483bf1419f |
310243312031 has 2 divisors, whose sum is σ = 310243312032. Its totient is φ = 310243312030.
The previous prime is 310243312021. The next prime is 310243312133. The reversal of 310243312031 is 130213342013.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 310243312031 - 214 = 310243295647 is a prime.
It is a super-2 number, since 2×3102433120312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 310243311988 and 310243312006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (310243312021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155121656015 + 155121656016.
It is an arithmetic number, because the mean of its divisors is an integer number (155121656016).
Almost surely, 2310243312031 is an apocalyptic number.
310243312031 is a deficient number, since it is larger than the sum of its proper divisors (1).
310243312031 is an equidigital number, since it uses as much as digits as its factorization.
310243312031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 310243312031 its reverse (130213342013), we get a palindrome (440456654044).
The spelling of 310243312031 in words is "three hundred ten billion, two hundred forty-three million, three hundred twelve thousand, thirty-one".
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