Base | Representation |
---|---|
bin | 1011100100001001… |
… | …1011000101001101 |
3 | 22000100111212212221 |
4 | 2321002123011031 |
5 | 22324212421143 |
6 | 1232014255341 |
7 | 136634064451 |
oct | 27102330515 |
9 | 8010455787 |
10 | 3104420173 |
11 | 1353400908 |
12 | 7277b7551 |
13 | 3a6214c1a |
14 | 216428661 |
15 | 13281d2ed |
hex | b909b14d |
3104420173 has 2 divisors, whose sum is σ = 3104420174. Its totient is φ = 3104420172.
The previous prime is 3104420149. The next prime is 3104420237. The reversal of 3104420173 is 3710244013.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2328352009 + 776068164 = 48253^2 + 27858^2 .
It is a cyclic number.
It is not a de Polignac number, because 3104420173 - 25 = 3104420141 is a prime.
It is a super-2 number, since 2×31044201732 = 19274849221058699858, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3104427173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1552210086 + 1552210087.
It is an arithmetic number, because the mean of its divisors is an integer number (1552210087).
Almost surely, 23104420173 is an apocalyptic number.
It is an amenable number.
3104420173 is a deficient number, since it is larger than the sum of its proper divisors (1).
3104420173 is an equidigital number, since it uses as much as digits as its factorization.
3104420173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
The square root of 3104420173 is about 55717.3238140527. The cubic root of 3104420173 is about 1458.7924231660.
Adding to 3104420173 its reverse (3710244013), we get a palindrome (6814664186).
The spelling of 3104420173 in words is "three billion, one hundred four million, four hundred twenty thousand, one hundred seventy-three".
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