3104425013 has 4 divisors (see below), whose sum is σ = 3141827808. Its totient is φ = 3067022220.

The previous prime is 3104424941. The next prime is 3104425019. The reversal of 3104425013 is 3105244013.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3105244013 = 1723 ⋅1802231.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3104425013 is a prime.

It is a super-2 number, since 2×3104425013² = 19274909322680100338, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3104425013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3104425019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18701273 + ... + 18701438.

It is an arithmetic number, because the mean of its divisors is an integer number (785456952).

Almost surely, 2^3104425013 is an apocalyptic number.

It is an amenable number.

3104425013 is a deficient number, since it is larger than the sum of its proper divisors (37402795).

3104425013 is an equidigital number, since it uses as much as digits as its factorization.

3104425013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37402794.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 3104425013 is about 55717.3672475647. The cubic root of 3104425013 is about 1458.7931812841.

Adding to 3104425013 its reverse (3105244013), we get a palindrome (6209669026).

The spelling of 3104425013 in words is "three billion, one hundred four million, four hundred twenty-five thousand, thirteen".