Base | Representation |
---|---|
bin | 1001000010001111110… |
… | …11100100100101101101 |
3 | 1002200022101222202102212 |
4 | 10201013323210211231 |
5 | 20041242234202023 |
6 | 354341033500205 |
7 | 31300050143414 |
oct | 4410773444555 |
9 | 1080271882385 |
10 | 310444444013 |
11 | 10a727882710 |
12 | 501bb271665 |
13 | 2337591bbb2 |
14 | 1105031847b |
15 | 811e5ade78 |
hex | 4847ee496d |
310444444013 has 4 divisors (see below), whose sum is σ = 338666666208. Its totient is φ = 282222221820.
The previous prime is 310444444003. The next prime is 310444444021.
310444444013 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 310444444013 - 212 = 310444439917 is a prime.
It is a super-3 number, since 3×3104444440133 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (310444444003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14111111081 + ... + 14111111102.
It is an arithmetic number, because the mean of its divisors is an integer number (84666666552).
Almost surely, 2310444444013 is an apocalyptic number.
It is an amenable number.
310444444013 is a deficient number, since it is larger than the sum of its proper divisors (28222222195).
310444444013 is a wasteful number, since it uses less digits than its factorization.
310444444013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28222222194.
The product of its (nonzero) digits is 36864, while the sum is 32.
It can be divided in two parts, 310444 and 444013, that added together give a palindrome (754457).
The spelling of 310444444013 in words is "three hundred ten billion, four hundred forty-four million, four hundred forty-four thousand, thirteen".
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