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3104455001 is a prime number
BaseRepresentation
bin1011100100001010…
…0011100101011001
322000100120122122212
42321002203211121
522324220030001
61232015124505
7136634301134
oct27102434531
98010518585
103104455001
111353424a9a
12727813735
133a6227a2b
1421643721b
151328287bb
hexb90a3959

3104455001 has 2 divisors, whose sum is σ = 3104455002. Its totient is φ = 3104455000.

The previous prime is 3104454971. The next prime is 3104455031. The reversal of 3104455001 is 1005544013.

It is a balanced prime because it is at equal distance from previous prime (3104454971) and next prime (3104455031).

It can be written as a sum of positive squares in only one way, i.e., 1775779600 + 1328675401 = 42140^2 + 36451^2 .

It is a cyclic number.

It is not a de Polignac number, because 3104455001 - 210 = 3104453977 is a prime.

It is not a weakly prime, because it can be changed into another prime (3104455031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1552227500 + 1552227501.

It is an arithmetic number, because the mean of its divisors is an integer number (1552227501).

Almost surely, 23104455001 is an apocalyptic number.

It is an amenable number.

3104455001 is a deficient number, since it is larger than the sum of its proper divisors (1).

3104455001 is an equidigital number, since it uses as much as digits as its factorization.

3104455001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 3104455001 is about 55717.6363551075. The cubic root of 3104455001 is about 1458.7978784662.

Adding to 3104455001 its reverse (1005544013), we get a palindrome (4109999014).

The spelling of 3104455001 in words is "three billion, one hundred four million, four hundred fifty-five thousand, one".