Base | Representation |
---|---|
bin | 1110001001001000010010… |
… | …00111101111000100101111 |
3 | 11002010010120020212012200222 |
4 | 13010210021013233010233 |
5 | 13034020310332304403 |
6 | 150051051541041555 |
7 | 6356621161415060 |
oct | 704441107570457 |
9 | 132103506765628 |
10 | 31100011213103 |
11 | 9a00493610678 |
12 | 35a34829b62bb |
13 | 14479456422a1 |
14 | 79736a132567 |
15 | 38deb1742338 |
hex | 1c49091ef12f |
31100011213103 has 8 divisors (see below), whose sum is σ = 35627697813120. Its totient is φ = 26593531576920.
The previous prime is 31100011213091. The next prime is 31100011213129. The reversal of 31100011213103 is 30131211000113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-31100011213103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31100011218103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5301737813 + ... + 5301743678.
It is an arithmetic number, because the mean of its divisors is an integer number (4453462226640).
Almost surely, 231100011213103 is an apocalyptic number.
31100011213103 is a deficient number, since it is larger than the sum of its proper divisors (4527686600017).
31100011213103 is a wasteful number, since it uses less digits than its factorization.
31100011213103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10603481917.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 31100011213103 its reverse (30131211000113), we get a palindrome (61231222213216).
The spelling of 31100011213103 in words is "thirty-one trillion, one hundred billion, eleven million, two hundred thirteen thousand, one hundred three".
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