31100401 has 2 divisors, whose sum is σ = 31100402. Its totient is φ = 31100400.

The previous prime is 31100389. The next prime is 31100411. The reversal of 31100401 is 10400113.

It is a happy number.

It is an a-pointer prime, because the next prime (31100411) can be obtained adding 31100401 to its sum of digits (10).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18147600 + 12952801 = 4260^2 + 3599^2 .

It is a cyclic number.

It is not a de Polignac number, because 31100401 - 2⁷ = 31100273 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (31100411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15550200 + 15550201.

It is an arithmetic number, because the mean of its divisors is an integer number (15550201).

Almost surely, 2^31100401 is an apocalyptic number.

It is an amenable number.

31100401 is a deficient number, since it is larger than the sum of its proper divisors (1).

31100401 is an equidigital number, since it uses as much as digits as its factorization.

31100401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 31100401 is about 5576.7733502447. The cubic root of 31100401 is about 314.4768371455.

Adding to 31100401 its reverse (10400113), we get a palindrome (41500514).

The spelling of 31100401 in words is "thirty-one million, one hundred thousand, four hundred one".