Base | Representation |
---|---|
bin | 11100111101110001… |
… | …010011010100100101 |
3 | 2222021111012212002021 |
4 | 130331301103110211 |
5 | 1002143340333240 |
6 | 22142044343141 |
7 | 2150500014544 |
oct | 347561232445 |
9 | 88244185067 |
10 | 31101105445 |
11 | 1220a843933 |
12 | 603b844ab1 |
13 | 2c18541c97 |
14 | 171079415b |
15 | c2062c54a |
hex | 73dc53525 |
31101105445 has 8 divisors (see below), whose sum is σ = 37351215000. Its totient is φ = 24860958720.
The previous prime is 31101105439. The next prime is 31101105461. The reversal of 31101105445 is 54450110113.
It can be written as a sum of positive squares in 4 ways, for example, as 3651905761 + 27449199684 = 60431^2 + 165678^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-31101105445 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2483836 + ... + 2496325.
It is an arithmetic number, because the mean of its divisors is an integer number (4668901875).
Almost surely, 231101105445 is an apocalyptic number.
It is an amenable number.
31101105445 is a deficient number, since it is larger than the sum of its proper divisors (6250109555).
31101105445 is a wasteful number, since it uses less digits than its factorization.
31101105445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4981415.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 31101105445 its reverse (54450110113), we get a palindrome (85551215558).
The spelling of 31101105445 in words is "thirty-one billion, one hundred one million, one hundred five thousand, four hundred forty-five".
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