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311012113 = 4738917011
BaseRepresentation
bin10010100010011…
…010101100010001
3210200020001102011
4102202122230101
51114104341423
650510022521
710464362566
oct2242325421
9720201364
10311012113
1114a616005
12881a7a41
134c585249
142d43c86d
151c486b0d
hex1289ab11

311012113 has 8 divisors (see below), whose sum is σ = 318464640. Its totient is φ = 303594480.

The previous prime is 311012089. The next prime is 311012123. The reversal of 311012113 is 311210113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 311012113 - 25 = 311012081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311012093 and 311012102.

It is not an unprimeable number, because it can be changed into a prime (311012123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9778 + ... + 26788.

It is an arithmetic number, because the mean of its divisors is an integer number (39808080).

Almost surely, 2311012113 is an apocalyptic number.

It is an amenable number.

311012113 is a deficient number, since it is larger than the sum of its proper divisors (7452527).

311012113 is a wasteful number, since it uses less digits than its factorization.

311012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17447.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 311012113 is about 17635.5355178118. The cubic root of 311012113 is about 677.5256912140.

Adding to 311012113 its reverse (311210113), we get a palindrome (622222226).

The spelling of 311012113 in words is "three hundred eleven million, twelve thousand, one hundred thirteen".

Divisors: 1 47 389 17011 18283 799517 6617279 311012113