Base | Representation |
---|---|
bin | 1110001001001010101111… |
… | …01110100011001110001100 |
3 | 11002010020222011102002100021 |
4 | 13010211113232203032030 |
5 | 13034031010440323040 |
6 | 150051430451311524 |
7 | 6356665644130003 |
oct | 704452756431614 |
9 | 132106864362307 |
10 | 31101330011020 |
11 | 9a00aaaa88005 |
12 | 35a37905ab5a4 |
13 | 1447ac592c499 |
14 | 797453347c3a |
15 | 38e03c3e724a |
hex | 1c4957ba338c |
31101330011020 has 12 divisors (see below), whose sum is σ = 65312793023184. Its totient is φ = 12440532004400.
The previous prime is 31101330010909. The next prime is 31101330011051. The reversal of 31101330011020 is 2011003310113.
It is a junction number, because it is equal to n+sod(n) for n = 31101330010985 and 31101330011003.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 777533250256 + ... + 777533250295.
It is an arithmetic number, because the mean of its divisors is an integer number (5442732751932).
Almost surely, 231101330011020 is an apocalyptic number.
It is an amenable number.
31101330011020 is an abundant number, since it is smaller than the sum of its proper divisors (34211463012164).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31101330011020 is a wasteful number, since it uses less digits than its factorization.
31101330011020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1555066500560 (or 1555066500558 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 31101330011020 its reverse (2011003310113), we get a palindrome (33112333321133).
The spelling of 31101330011020 in words is "thirty-one trillion, one hundred one billion, three hundred thirty million, eleven thousand, twenty".
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