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311021057 is a prime number
BaseRepresentation
bin10010100010011…
…100111000000001
3210200020111200102
4102202130320001
51114110133212
650510132145
710464430634
oct2242347001
9720214612
10311021057
1114a6217a6
12881b1055
134c589339
142d441c1b
151c4895c2
hex1289ce01

311021057 has 2 divisors, whose sum is σ = 311021058. Its totient is φ = 311021056.

The previous prime is 311021023. The next prime is 311021059. The reversal of 311021057 is 750120113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 176252176 + 134768881 = 13276^2 + 11609^2 .

It is a cyclic number.

It is not a de Polignac number, because 311021057 - 218 = 310758913 is a prime.

Together with 311021059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (311021059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155510528 + 155510529.

It is an arithmetic number, because the mean of its divisors is an integer number (155510529).

Almost surely, 2311021057 is an apocalyptic number.

It is an amenable number.

311021057 is a deficient number, since it is larger than the sum of its proper divisors (1).

311021057 is an equidigital number, since it uses as much as digits as its factorization.

311021057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 210, while the sum is 20.

The square root of 311021057 is about 17635.7890949058. The cubic root of 311021057 is about 677.5321858504.

The spelling of 311021057 in words is "three hundred eleven million, twenty-one thousand, fifty-seven".