Base | Representation |
---|---|
bin | 1110001001001110000110… |
… | …01100110101101010111111 |
3 | 11002010102121211021011021221 |
4 | 13010213003030311222333 |
5 | 13034043204034104043 |
6 | 150052325422134211 |
7 | 6360061430214106 |
oct | 704470314655277 |
9 | 132112554234257 |
10 | 31103133113023 |
11 | 9a01845870254 |
12 | 35a3bb4421367 |
13 | 144802236744a |
14 | 7975849cb03d |
15 | 38e0e58648ed |
hex | 1c49c3335abf |
31103133113023 has 4 divisors (see below), whose sum is σ = 31109668762480. Its totient is φ = 31096597463568.
The previous prime is 31103133112991. The next prime is 31103133113051. The reversal of 31103133113023 is 32031133130113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31103133113023 - 25 = 31103133112991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31103133113093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3267817590 + ... + 3267827107.
It is an arithmetic number, because the mean of its divisors is an integer number (7777417190620).
Almost surely, 231103133113023 is an apocalyptic number.
31103133113023 is a deficient number, since it is larger than the sum of its proper divisors (6535649457).
31103133113023 is an equidigital number, since it uses as much as digits as its factorization.
31103133113023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6535649456.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 31103133113023 its reverse (32031133130113), we get a palindrome (63134266243136).
The spelling of 31103133113023 in words is "thirty-one trillion, one hundred three billion, one hundred thirty-three million, one hundred thirteen thousand, twenty-three".
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